Q:

Graph g(x), where f(x) = 4x βˆ’ 2 and g(x) = f(x + 1).

Accepted Solution

A:
y = mx + b - it's a linear function.Two points are enough to draw a graph of a linear function.Step-by-step explanation:Two different ways.1.g(x) = f(x + 1) β†’ put instead of x, x + 1 into function f(x) = 4x - 2:g(x)=4(x + 1) - 2 Β  Β  use the distributive propertyg(x) = 4x + 4 - 2g(x) = 4x + 2Choose any two x values. Put them into the equation g(x) = y and calculate the values ​​of y.x = -1y = 4(-1) + 2 = -4 + 2 = -2 β†’ (-1, -2)x = 0y = 4(0) + 2 = 0 + 2 = 2 β†’ (0, 2)The graph on the picture #1.2.Use the transformation of a graph of a function:f(x) + n - shift the graph of f(x) n units upf(x) - n - shift the graph of f(x) n units downf(x + n) - shift the graph of f(x) n units to the leftf(x - n) - shift the graph of f(x) n units to the rightf(x) = 4x - 2, g(x) = f(x + 1)shift the graph of f(x) q unit to the left.Plot the graph of function f(x).Choose any two x values. Put them into the equation f(x) = y and calculate the values ​​of y.x = 0y = 4(0) - 2 = 0 - 2 = -2 β†’ (0, -2)x = 1y = 4(1) - 2 = 4 - 2 = 2 β†’ (1, 2)Plot the graph of f(x).Shift it 1 unit to the left.The graph on the picture #2.