Hugo is a veterinarian. He knows the following information about his 41 patrons: 20 patrons in total do not have a dog. 17 patrons in total have a cat. 7 patrons have neither a dog nor a cat. Can you help Hugo organize the results into a two-way frequency table?
Accepted Solution
A:
Start building the two-way frequency table: it will have three rows (cat, no cat, total) and three columns (dog, no dog, total).
Start filling the table with the data you know: | dog | no dog | total cat | | | 17 | no cat | | 7 | | total | | 20 | 41 |
Now you can make easy calculations in order to fill the blanks: - the number of patrons with cats but not dogs: (20 - 7) = 13; - the number of total dogs: (41 - 20) = 21 - the total number of patrons with no cats: (41 - 17) = 24.
Now the table looks like this: | dog | no dog | total cat | | 13 | 17 | no cat | | 7 | 24 | total | 21 | 20 | 41 |
And you can use the new data to complete the table: - the number of patrons with cats and dogs: (17 - 13) = 4 - the number of patrons with dogs and no cats: (24 - 7) = 17