a chemist mixed x millimeters of 25% acid solution with some 15% acid solution to produce 100 millimeters of a 19% acid solution. use this information to fill in the missing information in the table and answer the questions that follow

Answer:  40 ml of 25% solution  &   60 ml of 15% solutionStep-by-step explanation:[tex]\left\begin{array}{c|c|c|l}&Quantity&Percent&Total\ Solution\\Solution\ 1&x&25\%=0.25&0.25x\\\underline{Solution\ 2}&\underline{\ 100-x\ }&\underline{15\%=0.15}&\underline{\qquad \quad 0.15(100-x)}\\Mixture&100&19\%=0.19&0.25x+0.15(100-x)\end{array}\right\\\\\\Mixture: 100(0.19)=0.25x+0.15(100-x)\\.\qquad \qquad \qquad 19\ \quad =0.25x+15-0.15x\\.\qquad \qquad \qquad 4\qquad =0.10x\\\\.\qquad \qquad \quad \dfrac{4}{0.10}\qquad =\dfrac{0.10}{0.10}x\\\\.\qquad \qquad \qquad 40\qquad =x[/tex]Solution 1: x = 40Solution 2: 100 - x  --> 100 - 40 = 60